SAN FRANCISCO — Franchise icon Stephen Curry has officially secured his long-term future in the Bay Area. Ahead of training camp, the Golden State Warriors star agreed to a two-year, $116 million contract extension that binds him to the organization through the 2028–29 NBA season.
The agreement—reported by ESPN and confirmed by league sources—includes a player option for the final 2028–29 campaign, guaranteeing that the greatest shooter in basketball history will finish his storied career with the only franchise he has ever known.
A Team-First Discount for Future Flexibility
Curry was originally eligible to command a maximum extension worth up to $136.7 million. However, working closely with Warriors general manager Mike Dunleavy Jr., the four-time NBA champion opted for a slight pay cut—agreeing to $116 million—to grant the front office critical financial flexibility.
Curry’s salary will adjust from his upcoming $62.6 million earnings in the 2026–27 season down to $55.7 million for 2027–28, followed by a $60.2 million player option. By taking less than his max, Curry provides the Warriors with roughly $10 million in projected salary cap room next summer, enabling management to aggressively target upgrades in free agency or via the trade market.
“We’re in a very interesting situation,” Curry shared regarding his approach to the negotiations. “All the different salary cap conditions of whether I sign for a max or less or whatever it is, I want to be on a competitive team. I want to have an opportunity to have some flexibility because we haven’t had that in years past.”
Chasing Historic 20-Season Longevity
With this newly minted extension, Curry is set to play his 20th NBA season during the final year of the deal. Should he take the floor in 2028–29, he will enter an exclusive pantheon of legendary loyalty, joining Dirk Nowitzki (Dallas Mavericks), Kobe Bryant (Los Angeles Lakers), and Udonis Haslem (Miami Heat) as the only players in league history to spend 20 or more seasons with a single franchise.
